Question: Got this from SWMGamers: Is this still the rules for ranking players that are tied on points in a tournament? Also, what exactly do steps 3 through 5 mean? :

In the event of multiple players being tied for match points the following shall be used
to determine the final standings:
1. Total Wins-The player with the most wins.
2. Head to Head Matchups – The player who has won any head to head matchups would
be ahead of the loser in a head to head matchup.
3. SOS 1- The players strength of schedule minus the player's worst win.
4. SOS 2- As 3, factoring only the defeated players.
5. SOS 3-The players full strength of schedule
6. Roll Off-tied players will roll a D20, highest roll placing above the rest.

Actually I believe the bye only counts as a 3pt win but does not factor into SoS at all. This step is more about not punishing a player who was unlucky enough to play the opponent who does t win a single game.

so lets do an example. you play 5 opps and win 3 games and lose two. Opps record in parens.

rd 1 W (2-3)
rd 2 L (4-1)
rd 3 W (0-5)
rd 4 L (3-2)
rd 5 W (1-4)

So
TB 3 SOS minus worst win (the guy who went 0-5) is 10-10
TB 4 as 3 but factoring only defeated players (so no 4-1 or 3-2 losses or the 0-5 win) 3-7
TB 5 Full SOS counts everyone 10-15


Also if I recall, the way HTH works is only if the player has played everyone else. So if A,B,C,D all end tied going to step 2, A is only ahead if it beat all of the others. And once you determine one spot I believe you restart the loop. So if D has lost to all A,B,C, then that player would be the lowest of those 4, and you would restart the TB process for A,B,C.

But just because A beat B HTH doesn't mean that A is ranked ahead of B unless the TB is just between those two. Because it is possible that D beat A but lost to B creating an infinite loop. So HTH doesn't come into play very often, because it requires a very specific set of circumstances.

How byes are calculated are really the crux of the issue.

If I go 3-2, and one is a bye, I believe my SoS is all opponent's records added and then divided by 4 (not 5), thereby the bye is discluded altogether.

Here is another example. Again going 3-2 (although this time with a bye and a player who doesn't play all 5 rds)

W (bye)
W (1-2 drop)
W (4-1)
L (5-0)
L (4-1)

So

3 SOS minus worst win (1-2 drop is worst win) so would be 13-2
4 SOS same as 3 but only defeated opponents. Only beat one other player so 4-1
5 SOS full schedule 14-4

Again these are Tie Breakers for the SOS section.

I always thought The record of the player you beat with the most losses is dropped (not percentage). This way a person dropping doesn't hurt you as bad as a person continuing on and continuing to lose

Is this something we do not have defined previously? To this depth I mean...

Okay, do we know who decided on the criteria? Is this something the rules committee and/or the balance committee should figure out?

As long as everyone sticks around for the whole tournament, all 3 interpretations are identical, so probably hasn't been a reason to dive that deeply.

If you want the software to be flexible enough to work for multiple games/rules, sure. But for the SWMinis floor rules, I think you're safe just going with dropping the one that hurts the winning percentage the most.